From ab7bcbbbc6ba12ee3e8fd419b55b240ec33e581c Mon Sep 17 00:00:00 2001
From: Shawn <45581750+KOP-XIAO@users.noreply.github.com>
Date: Mon, 24 Jul 2023 17:03:03 +0800
Subject: [PATCH] update

---
 Scripts/resource-parser.js | 9 +++++----
 1 file changed, 5 insertions(+), 4 deletions(-)

diff --git a/Scripts/resource-parser.js b/Scripts/resource-parser.js
index c7397a1..896ecde 100644
--- a/Scripts/resource-parser.js
+++ b/Scripts/resource-parser.js
@@ -1,5 +1,5 @@
 /** 
-☑️ 资源解析器 ©𝐒𝐡𝐚𝐰𝐧  ⟦2023-07-18 17:05⟧
+☑️ 资源解析器 ©𝐒𝐡𝐚𝐰𝐧  ⟦2023-07-24 16:45⟧
 ----------------------------------------------------------
 🛠 发现 𝐁𝐔𝐆 请反馈: https://t.me/Shawn_Parser_Bot
 ⛳️ 关注 🆃🅶 相关频道: https://t.me/QuanX_API
@@ -479,6 +479,7 @@ function ResourceParse() {
     if (Prname) {
       Prn = Prname;
       total = total.map(Rename);
+      if(Pdbg==1) {$notify("rename","content",total)}
     }
     //2023-07-10 调整emoji操作顺序
     if (Pemoji) { total = emoji_handle(total, Pemoji); }
@@ -2364,8 +2365,8 @@ function DelReg(content) {
 function Rename(str) {
     var server = str;
     if (server.indexOf("tag=") != -1) {
-        hd = server.split("tag=")[0]
-        name = server.split("tag=")[1].split(",")[0].trim()
+        hd = server.split("tag=")[0] // 非 name 部分
+        name = server.split("tag=")[1].split(",")[0].trim() // name 部分
         tail = server.split("tag=")[1].split(",").length <=1 ? "" : server.split("tag=")[1].split(name)[1]
         for (var i = 0; i < Prn.length; i++) {
             nname = Prn[i].split("@")[1] ? decodeURIComponent(Prn[i].split("@")[1]) : Prn[i].split("@")[1];
@@ -2376,7 +2377,7 @@ function Rename(str) {
             } else if (oname && nname == "") {//前缀
                 var nemoji = emoji_del(name)
                 if ((Pemoji == 1 || Pemoji == 2) && Prname ) { //判断是否有重复 emoji，有则删除旧有
-                    name = name.replace(name.split(" ")[0] + " ", name.split(" ")[0] + " " + oname)
+                    name = oname + nemoji //name.replace(name.split(" ")[0] + " ", name.split(" ")[0] + " " + oname)
                 } else { name = oname + name.trim() }
             } else if (nname && oname == "") {//后缀
                 name = name.trim() + nname